5x^2-80x+63=0

Solution for 5x^2-80x+63=0 equation:

5x^2-80x+63=0

a = 5; b = -80; c = +63;
Δ = b2-4ac
Δ = -802-4·5·63
Δ = 5140
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5140}=\sqrt{4*1285}=\sqrt{4}*\sqrt{1285}=2\sqrt{1285}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-80)-2\sqrt{1285}}{2*5}=\frac{80-2\sqrt{1285}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-80)+2\sqrt{1285}}{2*5}=\frac{80+2\sqrt{1285}}{10}
$